CT Week 8 Graded Assignments IIT Madras

Computational Thinking week 8 graded assignment Complete Solutions Are Discussed In This Blog. We Hope This Might Help You All In Matching Answers . Or For Some Others Reasons If Not Able To Complete Graded Assignments

The following pseudocode is executed using the “Scores” dataset. What will the values of A and B represent at the end of the execution?

 
 
 
 
D = {}
while(Table 1 has more rows){
    Read the fist row X in Table 1
    if(isKey(D, X.Town/City)){
        if(D[X.Town/City] > X.Mathematics){
            D[X.Town/City] = X.Mathematics
        }
    }
    else{
        D[X.Town/City] = X.Mathematics
    }
    Move X to Table 2
}
  
A = 0, B = 100
foreach Y in keys(D){
    if(B == D[Y]){
        A = A + 1
    }
    if(B > D[Y]){
        A = 1
        B = D[Y]
    }
}
 

A = Cities where students score the highest marks in Mathematics
B = The highest marks in Mathematics

A = Number of cities where students score the highest marks in Mathematics
B = The highest marks in Mathematics

A = Number of cities where students score the lowest marks in Mathematics
B = The lowest marks in Mathematics

A = Always more than one
B = The highest marks in Mathematics

No, the answer is incorrect.
Score: 0

Accepted Answers:

A = Number of cities where students score the lowest marks in Mathematics
B = The lowest marks in Mathematics

4 points

2.The following pseudocode is executed using the “Scores” dataset. What will the value of B represent at the end of execution?

 
 
 
 
D = {}, B = 0
while(Table 1 has more rows){
    Read the first row X in Table 1
    D = updateDictByField(D, X.Physics)
    Move X to Table 2
}
B = findAKey(D
  
Procedure updateDictByField(D, Value)
    if(isKey(D, Value)){
        D[Value] = D[Value] + 1
    }
    else{
        D[Value] = 1
    }
    return(D)
End updateDictByField
  
Procedure findAKey(D)
    Key = -1, Value = 0
    foreach A in keys(D){
        if(D[A] > Value){
            Value = D[A]
            Key = A
        }
    }
    return(Key)
End findAKey
 

Number of repeated marks in Physics

Minimum marks in Physics

Maximum marks in Physics

Most frequent marks in Physics

No, the answer is incorrect.
Score: 0

Accepted Answers:

Most frequent marks in Physics

3.The following pseudocode is executed using the “Scores” dataset. What will be the value of B at the end of the execution?

 
 
 
 
D = {"Mathematics": {}, "Physics": {}, "Chemistry": {}}, B = 0
while(Table 1 has more rows){
    Read the first row X in Table 1
    D = updateDictByField(D, X, "Mathematics")
    D = updateDictByField(D, X, "Physics")
    D = updateDictByField(D, X, "Chemistry")
    Move X to Table 2
}
  
while(Table 2 has more rows){
    Read the first row X in Table 2
    if(eligible(D, X) > 1){
        B = B + 1
    }
    Move X to Table 1
}
  
Procedure updateDictByField(D, Y, Subject)
    if(isKey(D[Subject], Y.Town/City)){
        if(D[Subject][Y.Town/City] < Y.Subject){
            D[Subject][Y.Town/City] = Y.Subject
        }
    }
    else{
        D[Subject][Y.Town/City] = Y.Subject
    }
    return(D)
End updateDictByField
  
Procedure eligible(D, X)
    SubList = ["Mathematics", "Physics", "Chemistry"], C = 0
    foreach Subject in SubList{
        if(D[Subject][X.Town/City] == X.Subject){
            C = C + 1
        }
    }
    return(C)
End eligible
 

No, the answer is incorrect.
Score: 0

Accepted Answers:

(Type: Numeric) 10

6 points

5 points

4.The following pseudocode is executed using the “Shopping Bills” dataset. At the end of the execution, the variable D captures the following information: for each customer Z, D[Z] [“Shop”] stores the shops visited by Z, and D[Z] [“Category”] stores the categories of the items purchased by Z. But the pseudocode may have mistakes. Identify all such mistakes (if any). It is a Multiple Select Question (MSQ).

 
 
 
 
D = {}
while(Pile 1 has more cards){
    Read the top card X in Pile 1
    D = updateDictionary(D, X)
    Move X to Pile 2
}
Procedure updateDictionary(D, Y)
    if(not isKey(D, Y.CustomerName)){
        D[Y.CustomerName] = {"Shop": [], "Category": []}
    }
    D[Y.CustomerName]["Shop"][Y.ShopName] = True
    foreach A in Y.ItemList{
        D[Y.CustomerName]["Shop"][A.Category] = True
    }
    return(D)
End updateDictionary
 

No, the answer is incorrect.
Score: 0

Accepted Answers:

Error in Line 10

Error in Line 14

The following pseudocode is executed using the “station wise” cards of the “Train” dataset. At the end of the execution, STN captures the following information: for a station X, and a day of a week A, STN[X] [A] stores the number of trains running through X on the day A. [Note: Assume that for each station, the train list is given in a single card.]

 
STN = {}
while(Pile 1 has more cards){
    Read the top card X in Pile 1
    STN[X.StationName] = getInfo(STN, X)
    Move X to Pile 2
}

Procedure getInfo(STN, X) *** * Fill the code * *** return(D) End getInfo

4 points

Choose the correct code fragment to complete the pseudocode.

 
D = {}
foreach A in X.TrainList{
    foreach B in A.Days{
        D[B] = 1
    }
}

 
D = {"M": 0, "Tu": 0, "W": 0, "Th": 0, "F": 0, "Sa": 0, "Su": 0}
foreach A in X.TrainList{
    foreach B in A.Days{
        D[B] = 1
    }
}

 
D = {}
foreach A in X.TrainList{
    foreach B in A.Days{
        D[B] = D[B] + 1
    }
}

 
D = {"M": 0, "Tu": 0, "W": 0, "Th": 0, "F": 0, "Sa": 0, "Su": 0}
foreach A in X.TrainList{
    foreach B in A.Days{
        D[B] = D[B] + 1
    }
}

No, the answer is incorrect.
Score: 0

Accepted Answers:

D = {"M": 0, "Tu": 0, "W": 0, "Th": 0, "F": 0, "Sa": 0, "Su": 0} foreach A in X.TrainList{ foreach B in A.Days{ D[B] = D[B] + 1 } }

3 points

The following pseudocode is executed using the “station wise” cards of the “Train” dataset. Consider the dictionary STN computed in the previous question. Choose the correct statement(s) from the options based on the pseudocode. It is a Multiple Select Question (MSQ).

 
 
 
 
Z = {}, D = {}
foreach A in keys(STN){
    C = 0, Y = 0
    D = STN[A]
    foreach B in keys(D){
        if(Y == D[B]){
            C = C + 1
        }
        if(Y < D[B]){
            C = 1
            Y = D[B]
        }
    }
    if(not isKey(Z, C)){
        Z[C] = 0
    }
    Z[C] = Z[C] + 1
}
 

Keys of the dictionary Z is integer

There can be a value C such that Z[C] is zero

All values of the dictionary Z are non-zero

The number of keys in Z is 8

No, the answer is incorrect.
Score: 0

Accepted Answers:

Keys of the dictionary Z is integer

All values of the dictionary Z are non-zero

4 points

Consider the dictionary STN computed in the previous question. Choose the correct pseudocode to compute the number of stations which have trains passing through all days of a week.

 
 
 
 
 
Z = 0
foreach A in keys(STN){
    foreach B in keys(STN[A]){
        if(STN[A][B] < 1){
            C = False
        }
    }
    if(C){
        Z = Z + 1
    }
}
 

 
 
 
 
 
Z = 0
foreach A in keys(STN){
    C = True
    foreach B in keys(STN[A]){
        if(STN[A][B] < 1){
            C = False
        }
    }
    if(C){
        Z = Z + 1
    }
}
 
 

 
 
 
 
 
Z = 0
foreach A in keys(STN){
    C = True
    foreach B in keys(STN[A]){
        if(STN[A][B] < 1){
            C = False
        }
        else{
            C = True
        }
    }
    if(C){
        Z = Z + 1
    }
}
 
 

 
 
 
 
 
Z = 0
foreach A in keys(STN){
    C = False
    foreach B in keys(STN[A]){
        if(STN[A][B] < 1){
            C = True
        }
    }
    if(C){
        Z = Z + 1
    }
}
 

No, the answer is incorrect.
Score: 0

Accepted Answers:

Z = 0 foreach A in keys(STN){ C = True foreach B in keys(STN[A]){ if(STN[A][B] < 1){ C = False } } if(C){ Z = Z + 1 } }

The following pseudocode is executed using the “Words” table.

 
 
 
 
D = {}
while(Table 1 has more rows){
    Read the first row X in Table 1
    D = updateDictionary(D, X)
    Move X to Table 2
}
 Procedure updateDictionary(D, Y)
    i = 1
    while (i <= Y.LetterCount){
        B = ith letter in Y.Word
        if(isKey(D, B)){
            D[B] = D[B] + 1
        }
        else{
            D[B] = 1
        }
        i = i + 1
    }
    return(D)
End updateDictionary
 

3 points

What will D represent at the end of the execution?

Frequency count of each alphabet in the table

Frequency count of each word in the table

Most frequent alphabet in the table

Frequency count of each alphabet in each part of speech

No, the answer is incorrect.
Score: 0

Accepted Answers:

Frequency count of each alphabet in the table

4 points

Consider the dictionary D and the procedure updateDictionary() in the previous question. Let POS be a list that contains all part of speeches. Assume that given a dictionary D, there exists a procedure max such that max(D) returns a list of keys which are mapped to the maximum value. Choose the correct statement(s) from the options based on the following pseudocode. It is a Multiple Select Question (MSQ).

 
 
 
 
 
C = {"Overall": max(D)}
foreach A in POS{
    Move all rows to Table 1
    B = {}
    while (Table 1 has more rows){
        Read the first row X in Table 1
        if(X.PartOfSpeech == A){
            B = updateDictionary(B, X)
        }
        Move X to Table 2
    }
    C[A] = max(B)
}
 
 

length(keys(C)) is same as the number of different part of speeches in the input dataset

C captures the list of most frequent alphabet occurred overall in the dataset as well as for each part of speech

C captures the most frequent alphabet occurred overall in the dataset as well as for each part of speech

length(keys(C)) is one more than the number of different part of speeches in the dataset

No, the answer is incorrect.
Score: 0

Accepted Answers:

C captures the list of most frequent alphabet occurred overall in the dataset as well as for each part of speech

length(keys(C)) is one more than the number of different part of speeches in the dataset

4 points

The following pseudocode is executed using the “Shopping bills” dataset. What will D represent at the end of the execution?

 
 
 
 
D = {}
while(Pile 1 has more cards){
    Read the top card X in Pile 1
    D = updateDictionary(D, X)
    Move X to Pile 2
}
  
Procedure updateDictionary(D, Y)
    foreach A in Y.ItemList{
        C = A.ItemName
        if(isKey(D, C)){
            if(isKey(D[C], Y.ShopName)){
                if(D[C][Y.ShopName]["Price"] != A.Price){
                    D[C][Y.ShopName]["Flag"] = True
                }
            }
            else{
                D[C][Y.ShopName] = {"Price": A.Price, "Flag" : False}
            }
        }
        else{
            D[C] = {}
            D[C][Y.ShopName] = {"Price": A.Price, "Flag" : False}
        }
    }
    return (D)
End updateDictionary
 

For an item C, and a shop S, D[C] [S] [“Flag”] is set to True if and only if the item is sold for a constant price

For an item C, and a shop S, D[C] [S] [“Flag”] is set to True if and only if the item is billed in more than one bill

For an item C, and a shop S, D[C] [S] [“Flag”] is set to True if and only if the item is sold for variable price

For an item C, and a shop S, D[C] [S] [“Flag”] is set to True if and only if the item is billed exactly one bill

No, the answer is incorrect.
Score: 0

Accepted Answers:

For an item C, and a shop S, D[C] [S] [“Flag”] is set to True if and only if the item is sold for variable price

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CT Week 8 Graded Assignments IIT Madras

The following pseudocode is executed using the “Scores” dataset. What will the values of A and B represent at the end of the execution?

No, the answer is incorrect.Score: 0

Accepted Answers:

2.The following pseudocode is executed using the “Scores” dataset. What will the value of B represent at the end of execution?

No, the answer is incorrect.Score: 0

Accepted Answers:

3.The following pseudocode is executed using the “Scores” dataset. What will be the value of B at the end of the execution?

No, the answer is incorrect.Score: 0

Accepted Answers:

No, the answer is incorrect.Score: 0

Accepted Answers:

No, the answer is incorrect.Score: 0

Accepted Answers:

No, the answer is incorrect.Score: 0

Accepted Answers:

No, the answer is incorrect.Score: 0

Accepted Answers:

No, the answer is incorrect.Score: 0

Accepted Answers:

No, the answer is incorrect.Score: 0

Accepted Answers:

No, the answer is incorrect.Score: 0

Accepted Answers:

1 thought on “CT Week 8 Graded Assignments IIT Madras”

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No, the answer is incorrect.
Score: 0

No, the answer is incorrect.
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No, the answer is incorrect.
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No, the answer is incorrect.
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No, the answer is incorrect.
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No, the answer is incorrect.
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No, the answer is incorrect.
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No, the answer is incorrect.
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No, the answer is incorrect.
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No, the answer is incorrect.
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